document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=13454>Question 13454</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of an angle is 6 more than twice the measure of its complement.  Find the measures of both angles. Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6802 by </B><A HREF=/tutors/aboutme.mpl?userid=askmemath><B>askmemath(368)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=askmemath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6802\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Complementary angles sum up to 90degrees.\r<BR>\n" );
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document.write( "Let the smaller angle be X<BR>\n" );
document.write( "Then the larger angle becomes 2X+6\r<BR>\n" );
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document.write( "Sum = X + 2X+6  = 3X+6\r<BR>\n" );
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document.write( "3X +6 = 90<BR>\n" );
document.write( "3X = 84<BR>\n" );
document.write( "X = 84/3 = 28\r<BR>\n" );
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document.write( "Larger angle = 2(28)+6 = 62 </SPAN>\n" );
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