document.write( "Question 93420: Solve the system of equations using the addition (elimination) method. If the answer is a unique solution present it as an ordered pair: (x, y). If not specify whether the answer is \"no solution\" or \"infinitely many solutions. Can you show me how to work this problem so I can do my homwwork?\r
\n" ); document.write( "\n" ); document.write( "4x + y =4
\n" ); document.write( "2x + 8y =0
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Algebra.Com's Answer #68010 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"4%2Ax%2B1%2Ay=4\"
\n" ); document.write( " \"2%2Ax%2B8%2Ay=0\"
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\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
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\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
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\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 4 and 2 to some equal number, we could try to get them to the LCM.
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\n" ); document.write( " Since the LCM of 4 and 2 is 4, we need to multiply both sides of the top equation by 1 and multiply both sides of the bottom equation by -2 like this:
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\n" ); document.write( " \"1%2A%284%2Ax%2B1%2Ay%29=%284%29%2A1\" Multiply the top equation (both sides) by 1
\n" ); document.write( " \"-2%2A%282%2Ax%2B8%2Ay%29=%280%29%2A-2\" Multiply the bottom equation (both sides) by -2
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\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"4%2Ax%2B1%2Ay=4\"
\n" ); document.write( " \"-4%2Ax-16%2Ay=0\"
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\n" ); document.write( " Notice how 4 and -4 add to zero (ie \"4%2B-4=0\")
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\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%284%2Ax-4%2Ax%29%2B%281%2Ay-16%2Ay%29=4%2B0\"
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\n" ); document.write( " \"%284-4%29%2Ax%2B%281-16%29y=4%2B0\"
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\n" ); document.write( " \"cross%284%2B-4%29%2Ax%2B%281-16%29%2Ay=4%2B0\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
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\n" ); document.write( " So after adding and canceling out the x terms we're left with:
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\n" ); document.write( " \"-15%2Ay=4\"
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\n" ); document.write( " \"y=4%2F-15\" Divide both sides by \"-15\" to solve for y
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\n" ); document.write( " \"y=-4%2F15\" Reduce
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\n" ); document.write( " Now plug this answer into the top equation \"4%2Ax%2B1%2Ay=4\" to solve for x
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\n" ); document.write( " \"4%2Ax%2B1%28-4%2F15%29=4\" Plug in \"y=-4%2F15\"
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\n" ); document.write( " \"4%2Ax-4%2F15=4\" Multiply
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\n" ); document.write( " \"4%2Ax-4%2F15=4\" Reduce
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\n" ); document.write( " \"4%2Ax=4%2B4%2F15\" Subtract \"-4%2F15\" from both sides
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\n" ); document.write( " \"4%2Ax=60%2F15%2B4%2F15\" Make 4 into a fraction with a denominator of 15
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\n" ); document.write( " \"4%2Ax=64%2F15\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F4%29%284%29%29%2Ax=%2864%2F15%29%281%2F4%29\" Multiply both sides by \"1%2F4\". This will cancel out \"4\" on the left side.
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\n" ); document.write( " \"x=16%2F15\" Multiply the terms on the right side
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\n" ); document.write( " So our answer is
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\n" ); document.write( " \"x=16%2F15\", \"y=-4%2F15\"
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\n" ); document.write( " which also looks like
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\n" ); document.write( " (\"16%2F15\", \"-4%2F15\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"4%2Ax%2B1%2Ay=4\"
\n" ); document.write( " \"2%2Ax%2B8%2Ay=0\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"4%2Ax%2B1%2Ay=4\" (red) \"2%2Ax%2B8%2Ay=0\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
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\n" ); document.write( " and we can see that the two equations intersect at (\"16%2F15\",\"-4%2F15\"). This verifies our answer.

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