document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1064973>Question 1064973</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The current of a river is <BR>\n" );
document.write( "2<BR>\n" );
document.write( "2 miles per hour. A boat travels to a point <BR>\n" );
document.write( "24<BR>\n" );
document.write( "24 miles upstream and back in <BR>\n" );
document.write( "5<BR>\n" );
document.write( "5 hours. What is the speed of the boat in still water? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #680076 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=680076\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x= speed of boat<BR>\n" );
document.write( "(x-2) is speed upstream and 24/(x-2) is hours it takes to go 24 miles.<BR>\n" );
document.write( "(x+2) is speed downstream, and 24/(x+2) is hours it takes to go 24 miles.<BR>\n" );
document.write( "Those two times add to 5 hours<BR>\n" );
document.write( "Multiply by (x-2)(x+2) or x^2-4 as common denominator, <BR>\n" );
document.write( "24(x+2)+24(x-2)=5x^2-20<BR>\n" );
document.write( "0=5x^2-48x-20<BR>\n" );
document.write( "(5x+2)(x-10)=0<BR>\n" );
document.write( "x=10 mph in still water.<BR>\n" );
document.write( "so 8 mph upstream and takes 3 hours to go 24 miles<BR>\n" );
document.write( "and 12 mph downstream and takes 2 hours to go 24 miles.  Total time 5 hours. </SPAN>\n" );
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