document.write( "Question 1064965: Two fair number cubes are rolled. What is the probability of rolling a total greater than 6 OR rolling doubles?\r
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document.write( "Is the probability statement 21/36 + 6/36 or is it 21/36 + 3/36 ?\r
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document.write( "I don't know if you count the doubles only once, or in both statements \n" );
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Algebra.Com's Answer #680070 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! The total number of ways are 6+5+4+3+2+1=21, as you had. \n" ); document.write( "Rolling doubles are 6 ways, 3 of which are included in the 21 above. 11,22,33 are not included. \n" ); document.write( "Therefore, you count half of the doubles and don't count the other half, so it is the second, or 2/3 (24/36). \n" ); document.write( " |