document.write( "Question 93427This question is from textbook
\n" ); document.write( ": simplify please help me learn this and show all work. -sqrt(3) (sqrt (-3) \n" ); document.write( "
Algebra.Com's Answer #68007 by jim_thompson5910(35256)\"\" \"About 
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\"-sqrt%283%29%2Asqrt+%28-3%29\" Start with the given expression\r
\n" ); document.write( "\n" ); document.write( "\"-sqrt+%28-3%2A3%29\" Combine the roots using the identity \"sqrt%28x%29%2Asqrt%28y%29=sqrt%28x%2Ay%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"-sqrt+%28-9%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "Now lets focus on \"sqrt+%28-9%29\"\r
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Solved by pluggable solver: Simplifying Square Roots (whole numbers only)

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\n" ); document.write( " \"sqrt%28-9%29\" Start with the given expression
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\n" ); document.write( " \"sqrt%28-1%2A9%29\" Factor out a negative 1
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\n" ); document.write( " \"sqrt%28-1%29%2Asqrt%289%29\" Break up the square roots using the identity \"sqrt%28x%2Ay%29=sqrt%28x%29%2Asqrt%28y%29\"
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\n" ); document.write( " \"i%2Asqrt%289%29\" Replace \"sqrt%28-1%29\" with \"i\" (remember \"i=sqrt%28-1%29\")
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\n" ); document.write( " Now lets simplify \"sqrt%289%29\":
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\n" ); document.write( " Since 9 is a perfect square, we can take the square root of 9 to get a clean number
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\n" ); document.write( " \"sqrt%289%29=3\"
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\n" ); document.write( " So \"sqrt%28-9%29\" simplifies to \"3%2Ai\" (just reintroduce \"i\" back in)

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\n" ); document.write( "\n" ); document.write( "So \"-sqrt+%28-9%29=-3i\" (just reintroduce the negative back in)
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