document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=203>Question 203</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the original number is 2400 and you need to find 3 numbers to equal that number, one being 25% higher than the remaining 2 which are equal...how do I calulate that and get the answer? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #68 by </B><A HREF=/tutors/aboutme.mpl?userid=ichudov><B>ichudov(507)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ichudov><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ichudov><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=68\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Your task here is mainly to write an equation. Write it in words first:<BR>\r<BR>\n" );
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document.write( "number PLUS same number PLUS same 1.25 * number = 2400.<BR>\r<BR>\n" );
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document.write( "Replace number with x:<BR>\r<BR>\n" );
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document.write( "x + x + 1.25*x = 2400<BR>\r<BR>\n" );
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document.write( "3.25*x = 2400<BR>\r<BR>\n" );
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document.write( "this equation does not solve for a natural number x, the result is x = 738.461..., which makes me suspect that you either mis-stated the problem or I did not understand it. </SPAN>\n" );
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