document.write( "Question 1064873: In one region, the September energy consumption levels for single -family homes are found to be normally distributed with a mean of 1060 kWh and a standard deviation of 233 kWh. If 44 different homes are randomly selected, find the probability that their mean energy consumption level for September is greater than 1045 kWh. \n" ); document.write( "
Algebra.Com's Answer #679973 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! In one region, the September energy consumption levels for single -family homes are found to be normally distributed with a mean of 1060 kWh and a standard deviation of 233 kWh. If 44 different homes are randomly selected, find the probability that their mean energy consumption level for September is greater than 1045 kWh. \n" ); document.write( "----------------- \n" ); document.write( "z(1045) = (1045-1060)/(233/sqrt(44)) = -15*sqrt(44)/233 = -0.4270 \n" ); document.write( "==== \n" ); document.write( "P(x > 1045) = P(z > -0.4270) = 0.6653 \n" ); document.write( "---------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------ \n" ); document.write( " \n" ); document.write( " |