document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1064870>Question 1064870</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The ratios of the number of sweets Abigail has to the number of sweets Ben has is 4 : 5 at first. After Abigail bought another 16 sweets and Ben ate 2 sweets, Abigail has thrice as many sweets as Ben. How many sweets did Ben have in the end? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #679967 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=679967\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n be the common denominator of the sweets each have. Then<BR>\n" );
document.write( "4n+16:5n-2::3:1 So:<BR>\n" );
document.write( "4n+16=3(5n-2)<BR>\n" );
document.write( "4n+16=15n-6<BR>\n" );
document.write( "11n=22<BR>\n" );
document.write( "n=2<BR>\n" );
document.write( "At the beginning, Abigail has 4n, or 8 sweets; and Ben has 5n, or 10.  Ben then eats 2 sweets, leaving him with 8. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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