document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1064830>Question 1064830</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If given that tan(A) = 5 in Quadrant III and sin(B) = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+2%2F3+ ALIGN=MIDDLE  ALT=\"+2%2F3+\"   DISABLED_style= \"max-width:90%; height:auto;\" > in Quadrant II, what is the Quadrant of A-B? <BR>\n" );
document.write( "A.) I<BR>\n" );
document.write( "B.) II<BR>\n" );
document.write( "C.) III<BR>\n" );
document.write( "D.) IV </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #679932 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=679932\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The tangent of 5 in QIII is -5/-1 <BR>\n" );
document.write( "That is 78 degrees in QI or at 258.69 degrees<BR>\n" );
document.write( "Sin of 2/3 is the angle less than 180 or 41.8 less or 138.2 degrees.<BR>\n" );
document.write( "A-B=120.5 degrees, QuadrantII<BR>\n" );
document.write( "B. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );