document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1064790>Question 1064790</A>: <I><SPAN STYLE=\"word-break: break-all;\"> [(3x-1)/8] - [(2x+1)/3] = [(1-x)/4] - 1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #679922 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=679922\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> [(3x-1)/8] - [(2x+1)/3] = [(1-x)/4] - 1  Multiply everything by 24 to clear the fractions<BR>\n" );
document.write( "3(3x-1)-8(2x+1)=6(1-x)-24<BR>\n" );
document.write( "9x-3-16x-8=6-6x-24; collect terms<BR>\n" );
document.write( "-x=-7<BR>\n" );
document.write( "x=7<BR>\n" );
document.write( "Check<BR>\n" );
document.write( "(20/8)-(15/3)=(-6/4)-1<BR>\n" );
document.write( "2 1/2 -5=-1 1/2-1<BR>\n" );
document.write( "-2 1/2= -2 1/2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );