document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1064810>Question 1064810</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the equation of a line that is perpendicular to  &#8722;x+3y=9 and passes through the point (&#8722;3,2)? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #679915 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=679915\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> rewrite as 3y=x+9 and divide by 3 to get y=(1/3)x+3.<BR>\n" );
document.write( "The slope is (1/3), so the perpendicular line has a negative reciprocal, meaning the product of both slope is -1.  The slope of the perpendicular line is -3.<BR>\n" );
document.write( "point slope formula for (-3,2)<BR>\n" );
document.write( "y-y1=m(x-x1), m the slope, (x1,y1) the point<BR>\n" );
document.write( "y-2=-3(x-(-3))<BR>\n" );
document.write( "y-2=-3x-9<BR>\n" );
document.write( "y=-3x-7<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );