document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1064785>Question 1064785</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of the rectangular lot is 6 more then its widht. If the perimeter is 152 m. What are its dimensions? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #679874 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=679874\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2L+2W = Perimeter<BR>\n" );
document.write( "and<BR>\n" );
document.write( "L = W+6 substitute is the formula above:<BR>\n" );
document.write( "2(W+6)+2W = 152<BR>\n" );
document.write( "2W+12+2W = 152<BR>\n" );
document.write( "4W = 140<BR>\n" );
document.write( "W = 35<BR>\n" );
document.write( "L = W+6 = 35+6 = 41<BR>\n" );
document.write( "---------------------------------<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "2L+2W = 152<BR>\n" );
document.write( "2(41)+2(35) = 152<BR>\n" );
document.write( "82+70 = 152 Correct.<BR>\n" );
document.write( ":<BR>\n" );
document.write( "John </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );