document.write( "Question 1064777: Find the smallest number that when divided by 2, 3, 4, 5, or 6, it leaves a remainder of one but when divided by 7 has no remainder.\r
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document.write( "my work:\r
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document.write( "So I first I found the LCM of 2, 3, 4, 5, 6 which is 60.\r
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document.write( "Then I added 1 to 60 which is 61.\r
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document.write( "Then I multiplied 61 by 7 repeatedly till it fulfilled the condition that remainder should be 1. I got the answer 146461 which seems to correct but not completely sure. \r
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Algebra.Com's Answer #679863 by ikleyn(52943) You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "Let N be our unknown number under the question.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Consider the number N-1.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "According to the condition, it is multiple of 2, 3, 4, 5 and 6.\r\n" ); document.write( "Hence, N-1 is the multiple of 60.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "It means that our N is somewhere among these numbers: \r\n" ); document.write( "\r\n" ); document.write( "60+1, 2*60+1, 3*60+1, 4*60+1, 5*60+1, 6*60+1\r\n" ); document.write( "\r\n" ); document.write( "i.e, among the numbers 61, 121, 181, 241, 301.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Check, which of these numbers is multiple of 7.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Answer. 301.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "See the lesson\r \n" ); document.write( "\n" ); document.write( " - The number that leaves a remainder 1 when divided by 2, by 3, by 4, by 5 and so on until 9\r \n" ); document.write( "\n" ); document.write( "in this site.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |