document.write( "Question 1064744: Ms. Jamison plans to invest $3,800 in two accounts for one year. The first account earns a yearly interest of 3.5%. The second account earns a yearly interest of 6%. How much money does Ms. Jamison need to invest in the second account in order to earn $188 in interest from both accounts? \n" ); document.write( "
Algebra.Com's Answer #679841 by stanbon(75887)\"\" \"About 
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Ms. Jamison plans to invest $3,800 in two accounts for one year. The first account earns a yearly interest of 3.5%. The second account earns a yearly interest of 6%. How much money does Ms. Jamison need to invest in the second account in order to earn $188 in interest from both accounts?
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\n" ); document.write( "Quantity:: t + s = 3800 dollars
\n" ); document.write( "Interest:: 0.035t + 0.06s = 188 dollars
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\n" ); document.write( "35t + 35s = 35*3800
\n" ); document.write( "35t + 60s = 188000
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\n" ); document.write( "Subtract and solve for \"s\"::
\n" ); document.write( "25s = 55000
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\n" ); document.write( "s = $2200 (amt.invested at 6%)
\n" ); document.write( "t = 3800-2200 = $1600 (amt. invested at 3.5%)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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