document.write( "Question 1064659: Solve for x between 0 and 2pi (both included):
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document.write( "sin(4x) = cos(2x).
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document.write( "I changed sin(4x) into sin(2x+2x) so that I could use the identity so it would then become sin 2xcos2x + cos2xsin2x = cos 2x. I collected the like terms to give: 2sin 2xcos2x = cos 2x. My question is if it's possible to divide both sides by cos 2x? Or would I lose some of the values by doing so? \n" );
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Algebra.Com's Answer #679738 by Alan3354(69443) You can put this solution on YOUR website! I collected the like terms to give: 2sin 2xcos2x = cos 2x. My question is if it's possible to divide both sides by cos 2x? Or would I lose some of the values by doing so? \n" ); document.write( "------------ \n" ); document.write( "don't divide by it. \n" ); document.write( "2sin 2xcos2x - cos 2x = 0 \n" ); document.write( "cos(2x)*(2sin(2x) - 1) = 0 \n" ); document.write( "--- \n" ); document.write( "cos(2x) = 0 \n" ); document.write( "sin(2x) = 1/2 \n" ); document.write( "etc\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |