document.write( "Question 1064624: According to this relation the value of Y when X = 5 is? Then teacher gives a table X= 0, 1, 2, 3, 4 than Y=0, 3, 12, 27, 48. We have to add 5 for X and what for Y? please help. We have to show work and answer a multiply choice question which is A=67, B=70, C=73, D=75\r
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Algebra.Com's Answer #679713 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! We have the sequence \n" ); document.write( ": \n" ); document.write( "0, 3, 12, 27, 48 \n" ); document.write( "; \n" ); document.write( "we use the differences approach - we look for a level where the differences are the same \n" ); document.write( ": \n" ); document.write( "first level differences are 3, 9, 15, 21 \n" ); document.write( "second level differences are 6, 6, 6 \n" ); document.write( ": \n" ); document.write( "we know the function is of the form y = k * x^2, where k is a constant \n" ); document.write( ": \n" ); document.write( "by inspection, the function is \n" ); document.write( ": \n" ); document.write( "y = 3 * x^2 \n" ); document.write( ": \n" ); document.write( "therefore, for x = 5 \n" ); document.write( ": \n" ); document.write( "y = 3 * 5^2 = 75 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |