document.write( "Question 1064589: The perimeter of the rectangular playing field is 430 yards. The length of the field is 5 yards less than triple the width. What are the dimensions of the playing field? \n" ); document.write( "
Algebra.Com's Answer #679664 by addingup(3677)\"\" \"About 
You can put this solution on YOUR website!
2L+2W = 430
\n" ); document.write( "L = 3W-5
\n" ); document.write( "2(3W-5)+2W = 430
\n" ); document.write( "6W-10+2W = 430
\n" ); document.write( "8W = 440
\n" ); document.write( "W = 55 and L = 3(55)-5 = 160
\n" ); document.write( "----------------------------
\n" ); document.write( "Check:
\n" ); document.write( "2L+2W = 430
\n" ); document.write( "2(160)+2(55) = 430
\n" ); document.write( "320+110 = 430 Correct.
\n" ); document.write( ":
\n" ); document.write( "John
\n" ); document.write( "
\n" );