document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=93334>Question 93334</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi I am needing a little help on some algebra. Could you help me solve this: <BR>\n" );
document.write( "Is the point (-120,-99) on the graph of the line. Y=4/5x-3? Explain why or why not. I have tried and can't come up with anything. Thanks for your time </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #67966 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=67966\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The point (-120,-99) is in the standard form (x,y) which means x = -120 and y = -99.<BR>\n" );
document.write( "If that point is on the graph of the line that represents the equation:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+%284%2F5%29%2Ax+-3 ALIGN=MIDDLE  ALT=\"y+=+%284%2F5%29%2Ax+-3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "then if you substitute -99 for y and -120 for x both sides of the equation will be <BR>\n" );
document.write( "equal and that will prove that the point is on the line. Let's try it ...<BR>\n" );
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document.write( "Substituting -99 for y and -120 for x changes the equation to:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-99+=+%284%2F5%29%2A%28-120%29+-3 ALIGN=MIDDLE  ALT=\"-99+=+%284%2F5%29%2A%28-120%29+-3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ".<BR>\n" );
document.write( "If you multiply <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%284%2F5%29%2A%28-120%29 ALIGN=MIDDLE  ALT=\"%284%2F5%29%2A%28-120%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > you multiply the 4 times the -120 to get -480 and then you <BR>\n" );
document.write( "divide that by the denominator 5 to get -96. Substituting -96 for <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%284%2F5%29%2A%28-120%29 ALIGN=MIDDLE  ALT=\"%284%2F5%29%2A%28-120%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "the equation then becomes:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-99+=+-96+-+3 ALIGN=MIDDLE  ALT=\"-99+=+-96+-+3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "and on the right side if you combine -96 and - 3 you get -99.  That reduces the equation to:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-99+=+-99 ALIGN=MIDDLE  ALT=\"-99+=+-99\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Both sides of the equation are equal when x = -120 and y = -99.<BR>\n" );
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document.write( "This shows the equation is true for the point (-120,-99). Therefore, since the x and y values<BR>\n" );
document.write( "of the point make the equation true, you can say that the point (-120,-99) is on the graph <BR>\n" );
document.write( "of the equation:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+%284%2F5%29%2Ax+-3 ALIGN=MIDDLE  ALT=\"y+=+%284%2F5%29%2Ax+-3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Hope this helps you to understand the problem and what you have to do to show whether<BR>\n" );
document.write( "points are or are not on the graph of an equation.<BR>\n" );
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