document.write( "Question 1064537: suppose you work in a lab. You need a 200ml of a 35% acid solution for a certain test, but your supplier only ships a 25% solution and a 50% solution. Rather than pay ther hefty surcharge to have the supplier make a 35% solution, you decide to mix 25% acid solution with 50% acid solution, to make your own 35% acid solution. How many milliliters of each solution should you use to form 200ml of a 35% acid solution? \n" ); document.write( "

Algebra.Com's Answer #679602 by stanbon(75887) $\"\"$ $\"About$

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): suppose you work in a lab. You need a 200ml of a 35% acid solution for a certain test, but your supplier only ships a 25% solution and a 50% solution. Rather than pay ther hefty surcharge to have the supplier make a 35% solution, you decide to mix 25% acid solution with 50% acid solution, to make your own 35% acid solution. How many milliliters of each solution should you use to form 200ml of a 35% acid solution?
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\n" ); document.write( "Equation:
\n" ); document.write( "acid + acid = acid
\n" ); document.write( "0.25x + 0.50(200-x) = 0.35*200
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\n" ); document.write( "25x + 50*200 - 50x = 35*200
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\n" ); document.write( "-25x = -10*200
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\n" ); document.write( "x = 10*8 = 80 ml (amt. of 25% solution needed)
\n" ); document.write( "200-x = 120 ml (amt. of 50% solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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