document.write( "Question 1064523: Frank has nickels and dimes in his pocket. He has 25 coins in his pocket with a total value of $1.85. How many of each type of coin does he have? \n" ); document.write( "
Algebra.Com's Answer #679599 by Edwin McCravy(20056)\"\" \"About 
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document.write( "Two ways to do it.\r\n" );
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document.write( "1. Without algebra:\r\n" );
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document.write( "Suppose Frank started out with all 25 coins being nickels.  He'd \r\n" );
document.write( "then have only $1.25.  But Frank has 60 cents more than that, so \r\n" );
document.write( "he would need 12 more nickels, so he'd need to trade 12 of those \r\n" );
document.write( "nickels for dimes.  Therefore the answer is 12 dimes, and so the \r\n" );
document.write( "other 13 coins are nickels.\r\n" );
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document.write( "2.  With algebra:\r\n" );
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document.write( "        N + D = 25\r\n" );
document.write( "0.05N + 0.10D = 1.85 \r\n" );
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document.write( "Multiply the second one through by 100\r\n" );
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document.write( "        N +   D =  25 \r\n" );
document.write( "       5N + 10D = 185\r\n" );
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document.write( "Solve that system by substitution or elimination, and you'll\r\n" );
document.write( "get N=13, D=12.\r\n" );
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document.write( "Edwin
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