document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1064480>Question 1064480</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is three times as long as its width. If each side is increased by 6, the area of a new rectangle is 156 more than the area of the original rectangle. What are the dimensions of the new rectangle?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #679596 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=679596\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let w be the width of the rectangle. Then the length would be 3w. Now let a be the area of the original rectangle. Then the area of the new rectangle would be n+156. So:<BR>\n" );
document.write( "w(3w)=n<BR>\n" );
document.write( "3w²=n and<BR>\n" );
document.write( "(w+6)(3w+6)=n+156<BR>\n" );
document.write( "3w²+24w+36=n+156<BR>\n" );
document.write( "24w=120<BR>\n" );
document.write( "w=5<BR>\n" );
document.write( "The original width of the rectangle was 5 units, and the old length was 15 units. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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