document.write( "Question 1064149: If 100,000 kg of water (in the upper meter) is stored behind a small hydroelectric dam 50m tall. How much energy is stored in the water(assuming the turbines are installed at the bottom of the dam)? If a turning could be made 100% effeicient, how much power can the turbine produce if the water slows from 12.0m/s to 8.0 m/s in the .5 second it is in contact with the turbine? How much force did the water place on the turbine? \n" ); document.write( "
Algebra.Com's Answer #679549 by Fombitz(32388)\"\" \"About 
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All the energy is stored as potential energy,
\n" ); document.write( "\"P=mgh\"
\n" ); document.write( "\"P=100000%289.8%29%2850%29\"
\n" ); document.write( "\"P=4.9x10%5E7\"\"J\"
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\n" ); document.write( "So the difference in kinetic energy is transferred,
\n" ); document.write( "\"KE=%281%2F2%29mV%5E2\"
\n" ); document.write( "\"DELTA%2AKE=%281%2F2%29%28100000%29%2812%5E2-8%5E2%29\"
\n" ); document.write( "\"DELTA%2AKE=5.95x10%5E6\"\"J\"
\n" ); document.write( "So power would be KE per unit time,
\n" ); document.write( "\"W=5.95x10%5E6%2F0.5=1.2x10%5E7\"\"watts\"
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