document.write( "Question 1064358: Wendy was awarded a volleyball scholarship to the University of Michigan, so on graduation her parents gave her the $22,000 they had saved for her college tuition. She opted to invest some money in a privately held company that pays 10 % per year and evenly split the remaining money between a money market account yielding 2 % and a high-risk stock that yielded 40 %. At the end of the first year she had $26,400 total. How much did she invest in each of the three? \n" ); document.write( "
Algebra.Com's Answer #679463 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! Let n be the amount of money invested at 10% per year. Then the remaining money is 22000-n. This gets split into two; being .5(22000-n) and another .5(22000-n). If she has $26400 after her first year, she has made 26400-22000=$4400 interest. So: \n" ); document.write( ".1(n)+.02(.5(22000-n)+.4(.5(22000-n)=4400 \n" ); document.write( "4620-.11n=4400 \n" ); document.write( ".11n=220 \n" ); document.write( "n=2000 \n" ); document.write( "22000-n=20000 \n" ); document.write( "20000/2=10000 \n" ); document.write( "$2000 was invested at 10%; and $10000 was invested at 2% and 40% each. ☺☺☺☺ \n" ); document.write( " |