document.write( "Question 1064404: Maureen had $2000 to deposit. How much should she deposit at 12% interest, and how much should she invest at 10% if she wishes to earn $230 in interest this year? \n" ); document.write( "
Algebra.Com's Answer #679458 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! Let n be the amount to be invested at 12%. Then the amount to be invested at 10% would be 2000-n. So: \n" ); document.write( ".12n+.1(2000-n)=230 \n" ); document.write( ".02n=30 \n" ); document.write( "n=30/.02=$1500 to be invested at 12%, and $500 to be invested at 10%. ☺☺☺☺ \n" ); document.write( " |