document.write( "Question 1064393: Find the equation of the circle satisfying the given conditions (general equation)\r
\n" ); document.write( "\n" ); document.write( "1. Tangent to the line 4x-3y=6 at (3,2) and passing through (2,-1).
\n" ); document.write( "

Algebra.Com's Answer #679448 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
Find the equation of the circle satisfying the given conditions (general equation)\r
\n" ); document.write( "\n" ); document.write( "1. Tangent to the line 4x-3y=6 at (3,2) and passing through (2,-1).
\n" ); document.write( "--------------
\n" ); document.write( "Find the line thru (3,2) perpendicular to the given line.
\n" ); document.write( "The center will be on that line.
\n" ); document.write( "----
\n" ); document.write( "Find the perpendicular bisector of the line between (3,2) and (2,-1).
\n" ); document.write( "The center is also on that line.
\n" ); document.write( "The intersection of the 2 lines is the center, (h,k).
\n" ); document.write( "-----
\n" ); document.write( "The distance from the center to either point is the radius r.
\n" ); document.write( "\"%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2\"
\n" ); document.write( "--------------------------------
\n" ); document.write( "The 2 lines are
\n" ); document.write( "x + 3y = 4 Eqn A
\n" ); document.write( "3x + 4y = 17 Eqn B
\n" ); document.write( "3x + 9y = 12 Eqn A times 3
\n" ); document.write( "------------------------------- subtract
\n" ); document.write( "-5y = 5
\n" ); document.write( "y = -1
\n" ); document.write( "---
\n" ); document.write( "x = 7
\n" ); document.write( "--> center @ (7,-1)
\n" ); document.write( "=========================
\n" ); document.write( "Using the point (3,2):
\n" ); document.write( "r^2 = diffy^2 + diffx^2 = 9 + 16 = 25
\n" ); document.write( "-----
\n" ); document.write( "\"%28x-7%29%5E2+%2B+%28y%2B1%29%5E2+=+25\" is the circle.
\n" ); document.write( "-----------
\n" ); document.write( "I'll check it tomorrow.
\n" ); document.write( "
\n" ); document.write( "
\n" );