document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1064395>Question 1064395</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would you solve The design shows a rectangular home with a width that is 11 feet shorter than its length and an area of 900 square feet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #679446 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=679446\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How would you solve The design shows a rectangular home with a width that is 11 feet shorter than its length and an area of 900 square feet?<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "W = L - 11<BR>\n" );
document.write( "W*L = 900<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Sub for W<BR>\n" );
document.write( "L*(L-11) = 900<BR>\n" );
document.write( "L^2 - 11L - 900 = 0<BR>\n" );
document.write( "(L - 36)*(L + 25) = 0<BR>\n" );
document.write( "L = 36<BR>\n" );
document.write( "W = 25 </SPAN>\n" );
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