document.write( "Question 1064355: Express the following as a single logarithm (base is 10 unless otherwise indicated):\r
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document.write( "log2-log3+log5=
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document.write( "log2-(log3+log5)=
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document.write( "log2-log(3*5)=
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document.write( "log2-log15=
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document.write( "log(2/5)=0.8751\r
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document.write( "Now, I did this problem this way and answers don't match. Please explain why? Thank you very much. \r
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document.write( "(log2-log3)+log5=
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document.write( "log(2/3)+log5=
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document.write( "log((2/3)*5)=
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document.write( "log(10/3)=0.5228\r
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document.write( "Now, which one is the solution to the question? I am confused!!!!!!!!!! Thank you very much. \n" );
document.write( "
Algebra.Com's Answer #679405 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "As decimal value approximation, 0.52288\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----------Note: in log base 10, \n" ); document.write( " \n" ); document.write( " |