document.write( "Question 1064321: Assume that women's heights are normally distributed with a mean given by mu equals 62.4 in, and a standard deviation given by sigma equals 1.8 in.\r
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document.write( "(a) If 1 woman is randomly selected, find the probability that her height is less than 63 in.\r
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document.write( "(b) If 30 women are randomly selected, find the probability that they have a mean height less than 63 in.\r
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document.write( "(a)The probability is approximately . 6293
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document.write( "(Round to four decimal places as needed.)
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document.write( "(b) The probability is approximately
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document.write( "I have (A) I need help with Part B. \n" );
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Algebra.Com's Answer #679362 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Assume that women's heights are normally distributed with a mean given by mu equals 62.4 in, and a standard deviation given by sigma equals 1.8 in. \n" ); document.write( "(a) If 1 woman is randomly selected, find the probability that her height is less than 63 in. \n" ); document.write( "(b) If 30 women are randomly selected, find the probability that they have a mean height less than 63 in. \n" ); document.write( "----- \n" ); document.write( "For samples of size 30 the standard deviation becomes 1.8/sqrt(30). \n" ); document.write( "z(63) = (63-62.4)/(1.8/sqrt(30)) = 1.8257 \n" ); document.write( "P(x-bar< 63) = P(z < 1.8257) = normalcdf(-100,1.8257) = 0.9661 \n" ); document.write( "-----------\r \n" ); document.write( "\n" ); document.write( "a)The probability is approximately 0.6293 \n" ); document.write( "(b) The probability is approximately 0.9661 \n" ); document.write( "------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "---------- \n" ); document.write( " |