document.write( "Question 1064321: Assume that​ women's heights are normally distributed with a mean given by mu equals 62.4 in, and a standard deviation given by sigma equals 1.8 in.\r
\n" ); document.write( "\n" ); document.write( "​(a) If 1 woman is randomly​ selected, find the probability that her height is less than 63 in.\r
\n" ); document.write( "\n" ); document.write( "​(b) If 30 women are randomly​ selected, find the probability that they have a mean height less than 63 in.\r
\n" ); document.write( "\n" ); document.write( "​(​a)The probability is approximately . 6293
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\n" ); document.write( "​(Round to four decimal places as​ needed.)
\n" ); document.write( "​(b) The probability is approximately
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\n" ); document.write( "\n" ); document.write( "I have (A) I need help with Part B.
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Algebra.Com's Answer #679362 by stanbon(75887)\"\" \"About 
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Assume that​ women's heights are normally distributed with a mean given by mu equals 62.4 in, and a standard deviation given by sigma equals 1.8 in.
\n" ); document.write( "​(a) If 1 woman is randomly​ selected, find the probability that her height is less than 63 in.
\n" ); document.write( "​(b) If 30 women are randomly​ selected, find the probability that they have a mean height less than 63 in.
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\n" ); document.write( "For samples of size 30 the standard deviation becomes 1.8/sqrt(30).
\n" ); document.write( "z(63) = (63-62.4)/(1.8/sqrt(30)) = 1.8257
\n" ); document.write( "P(x-bar< 63) = P(z < 1.8257) = normalcdf(-100,1.8257) = 0.9661
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\n" ); document.write( "\n" ); document.write( "a)The probability is approximately 0.6293
\n" ); document.write( "(b) The probability is approximately 0.9661
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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