document.write( "Question 93319: Can you help me with this problem? Solve for x. x+2y= -1
\n" ); document.write( " 3x-4y= 27
\n" ); document.write( "I think I am supposed to solve for y in one problem, then substitute it in the next one... but I'm not sure. Thanks in advance!!!
\n" ); document.write( "

Algebra.Com's Answer #67933 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming you want to solve this system using substitution right?\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Solving a linear system of equations by subsitution

\n" ); document.write( "
\n" ); document.write( " Lets start with the given system of linear equations
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax%2B2%2Ay=-1\"
\n" ); document.write( " \"3%2Ax-4%2Ay=27\"
\n" ); document.write( "
\n" ); document.write( " Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to choose y.
\n" ); document.write( "
\n" ); document.write( " Solve for y for the first equation
\n" ); document.write( "
\n" ); document.write( " \"2%2Ay=-1-1%2Ax\"Subtract \"1%2Ax\" from both sides
\n" ); document.write( "
\n" ); document.write( " \"y=%28-1-1%2Ax%29%2F2\" Divide both sides by 2.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Which breaks down and reduces to
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=-1%2F2-%281%2F2%29%2Ax\" Now we've fully isolated y
\n" ); document.write( "
\n" ); document.write( " Since y equals \"-1%2F2-%281%2F2%29%2Ax\" we can substitute the expression \"-1%2F2-%281%2F2%29%2Ax\" into y of the 2nd equation. This will eliminate y so we can solve for x.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax%2B-4%2Ahighlight%28%28-1%2F2-%281%2F2%29%2Ax%29%29=27\" Replace y with \"-1%2F2-%281%2F2%29%2Ax\". Since this eliminates y, we can now solve for x.
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax-4%2A%28-1%2F2%29-4%28-1%2F2%29x=27\" Distribute -4 to \"-1%2F2-%281%2F2%29%2Ax\"
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax%2B4%2F2%2B%284%2F2%29%2Ax=27\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax%2B2%2B2%2Ax=27\" Reduce any fractions
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax%2B2%2Ax=27-2\" Subtract \"2\" from both sides
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax%2B2%2Ax=25\" Combine the terms on the right side
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"5%2Ax=25\" Now combine the terms on the left side.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"cross%28%281%2F5%29%285%2F1%29%29x=%2825%2F1%29%281%2F5%29\" Multiply both sides by \"1%2F5\". This will cancel out \"5%2F1\" and isolate x
\n" ); document.write( "
\n" ); document.write( " So when we multiply \"25%2F1\" and \"1%2F5\" (and simplify) we get
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"x=5\" <---------------------------------One answer
\n" ); document.write( "
\n" ); document.write( " Now that we know that \"x=5\", lets substitute that in for x to solve for y
\n" ); document.write( "
\n" ); document.write( " \"3%285%29-4%2Ay=27\" Plug in \"x=5\" into the 2nd equation
\n" ); document.write( "
\n" ); document.write( " \"15-4%2Ay=27\" Multiply
\n" ); document.write( "
\n" ); document.write( " \"-4%2Ay=27-15\"Subtract \"15\" from both sides
\n" ); document.write( "
\n" ); document.write( " \"-4%2Ay=12\" Combine the terms on the right side
\n" ); document.write( "
\n" ); document.write( " \"cross%28%281%2F-4%29%28-4%29%29%2Ay=%2812%2F1%29%281%2F-4%29\" Multiply both sides by \"1%2F-4\". This will cancel out -4 on the left side.
\n" ); document.write( "
\n" ); document.write( " \"y=12%2F-4\" Multiply the terms on the right side
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=-3\" Reduce
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So this is the other answer
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=-3\"<---------------------------------Other answer
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So our solution is
\n" ); document.write( "
\n" ); document.write( " \"x=5\" and \"y=-3\"
\n" ); document.write( "
\n" ); document.write( " which can also look like
\n" ); document.write( "
\n" ); document.write( " (\"5\",\"-3\")
\n" ); document.write( "
\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax%2B2%2Ay=-1\"
\n" ); document.write( " \"3%2Ax-4%2Ay=27\"
\n" ); document.write( "
\n" ); document.write( " we get
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " graph of \"1%2Ax%2B2%2Ay=-1\" (red) and \"3%2Ax-4%2Ay=27\" (green) (hint: you may have to solve for y to graph these) intersecting at the blue circle.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " and we can see that the two equations intersect at (\"5\",\"-3\"). This verifies our answer.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " -----------------------------------------------------------------------------------------------
\n" ); document.write( " Check:
\n" ); document.write( "
\n" ); document.write( " Plug in (\"5\",\"-3\") into the system of equations
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Let \"x=5\" and \"y=-3\". Now plug those values into the equation \"1%2Ax%2B2%2Ay=-1\"
\n" ); document.write( "
\n" ); document.write( " \"1%2A%285%29%2B2%2A%28-3%29=-1\" Plug in \"x=5\" and \"y=-3\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"5-6=-1\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"-1=-1\" Add
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"-1=-1\" Reduce. Since this equation is true the solution works.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So the solution (\"5\",\"-3\") satisfies \"1%2Ax%2B2%2Ay=-1\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Let \"x=5\" and \"y=-3\". Now plug those values into the equation \"3%2Ax-4%2Ay=27\"
\n" ); document.write( "
\n" ); document.write( " \"3%2A%285%29-4%2A%28-3%29=27\" Plug in \"x=5\" and \"y=-3\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"15%2B12=27\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"27=27\" Add
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"27=27\" Reduce. Since this equation is true the solution works.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So the solution (\"5\",\"-3\") satisfies \"3%2Ax-4%2Ay=27\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Since the solution (\"5\",\"-3\") satisfies the system of equations
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax%2B2%2Ay=-1\"
\n" ); document.write( " \"3%2Ax-4%2Ay=27\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " this verifies our answer.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" );