document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1064247>Question 1064247</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The function f(x)=-4(x+2)^2+5 is transformed into the function g(x) by the rule g(x)=f(x-5)+7. What are the coordinates of the turning point of g(x)? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #679305 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=679305\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  The function f(x)=-4(x+2)^2+5 is transformed into the function g(x) by the rule g(x)=f(x-5)+7. What are the coordinates of the turning point of g(x)? <BR>\n" );
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document.write( "f(x-5) = 4(x-3)^2+5<BR>\n" );
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document.write( "So, g(x) = 4(x-3)^2+12 = 4(x^2-6x+9)+12 = 4x^2 - 24x + 48<BR>\n" );
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document.write( "Ans: Turning point = (-b/(2a),g(-b/2a))<BR>\n" );
document.write( "-b/(2a) = 24/8 = 3<BR>\n" );
document.write( "g(3) = 4*9-24*3+48 = 36-72+48 = -36+48 = 12<BR>\n" );
document.write( "Ans:: (3,12)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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