document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=93293>Question 93293</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve using a two-order system. <BR>\n" );
document.write( "One number is 3 less than twice another. If their sum is 39, find the numbers.\r<BR>\n" );
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document.write( "Solve using a two- order system.<BR>\n" );
document.write( "John made a rectangular pen for his dog using 28 feet of fencing. <BR>\n" );
document.write( "If the width of the pen is 2 feet more than one-half the length, what are the length and width of the pen? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #67920 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=67920\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+(2x-3)=90<BR>\n" );
document.write( "3x=90+3<BR>\n" );
document.write( "3x=93<BR>\n" );
document.write( "x=93/3<BR>\n" );
document.write( "x=31 for the first number &:<BR>\n" );
document.write( "2*31-3=62-3=59 for the second number.<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "31+59=90<BR>\n" );
document.write( "90=90 </SPAN>\n" );
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