document.write( "Question 93296: A man travels for Town X to Town Y at an average rate of 50 mph and returns at an average rate of 40 mph. He takes 1/2 hr. longer than he would take if he made the round trip at an average of 45 mph. What is the distance from Town X to Town Y? \n" ); document.write( "
Algebra.Com's Answer #67917 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! d/50+d/40=(2d/45)+.5 \n" ); document.write( "(40d+50d)/2000=(2d+22.5)/45 \n" ); document.write( "90d/2000=(2d+22.5)/45 now cross multiply. \n" ); document.write( "45*90d=4000d+45000 \n" ); document.write( "4050d-4000d=45000 \n" ); document.write( "50d=45000 \n" ); document.write( "d=45000/50 \n" ); document.write( "d=900 miles for the trip fron x to y. \n" ); document.write( "proof \n" ); document.write( "900/50+900/40=1800/45+.5 \n" ); document.write( "18+22.5=40+.5 \n" ); document.write( "40.5=40.5 \n" ); document.write( " \n" ); document.write( " |