document.write( "Question 1064121: If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation h=−16t^2+vt+s, where h is in feet. If the object is propelled from a height of 88 feet with an initial velocity of 96 feet per second, its height h is given by the equation h=−16t^2+96t+8.
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Algebra.Com's Answer #679166 by Alan3354(69443) $\"\"$ $\"About$

You can put this solution on YOUR website!
h=−16t^2+96t+8.
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\n" ); document.write( "I'll assume you meant 88 feet.
\n" ); document.write( "h=−16t^2+96t+88 = 148
\n" ); document.write( "Solve for t.
\n" ); document.write( "2 values for t, ascending and descending.
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