document.write( "Question 1064092: Solve the following equation for \"+0+\" ≤ x < 360.\r
\n" ); document.write( "\n" ); document.write( "\"+3+\"csc(x) + \"+5+\" = csc(x) + \"+9+\"\r
\n" ); document.write( "\n" ); document.write( "A.) \"+30+\"° & \"+150+\"°
\n" ); document.write( "B.) \"+150+\"° and \"+330+\"°
\n" ); document.write( "C.) \"+60+\"° & \"+120+\"°
\n" ); document.write( "D.) \"+120+\"° and \"+300+\"°
\n" ); document.write( "Thanks!
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Algebra.Com's Answer #679128 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"3%2Acsc%28x%29%2B5+=+csc%28x%29%2B9\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"3%2Acsc%28x%29%2B5-5+=+csc%28x%29%2B9-5\" Subtract 5 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"3%2Acsc%28x%29+=+csc%28x%29%2B4\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"3%2Acsc%28x%29-csc%28x%29+=+csc%28x%29%2B4-csc%28x%29\" Subtract csc(x) from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"2csc%28x%29+=+4\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"%282csc%28x%29%29%2F2+=+4%2F2\" Divide both sides by 2\r
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\n" ); document.write( "\n" ); document.write( "\"csc%28x%29+=+2\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F%28sin%28x%29%29+=+2%2F1\" Rewrite csc(x) in terms of sine. Rewrite the \"2\" on the right side as \"2/1\"\r
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\n" ); document.write( "\n" ); document.write( "\"sin%28x%29+=+1%2F2\" Apply reciprocals to both sides\r
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\n" ); document.write( "\n" ); document.write( "The goal now is to solve \"sin%28x%29+=+1%2F2\" or \"sin%28theta%29+=+1%2F2\" \r
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\n" ); document.write( "\n" ); document.write( "Use a unit circle to find points on the unit circle that have a y coordinate of y = 1/2. This happens at theta = 30 and theta = 150 (in Q1 and Q2 respectively)\r
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\n" ); document.write( "\n" ); document.write( "So that means x = 30 or x = 150 (where x is the angle in degrees). \r
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\n" ); document.write( "\n" ); document.write( "The final answer is Choice A) 30 degrees and 150 degrees
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