document.write( "Question 1064074: ΔABC has vertices at A(8,3), B(7,5), and C(2,4). Point D, located on AC¯ at approximately (6.7,3.22), is the intersection of the altitude drawn from B to AC¯.\r
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Algebra.Com's Answer #679117 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "ΔABC has vertices at A(8,3), B(7,5), and C(2,4). Point D, located on AC¯ at approximately (6.7,3.22), is the intersection of the altitude drawn from B to AC¯.\r
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\n" ); document.write( "\n" ); document.write( "The area of △ABC is _____ units2.
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Just calculate the length of AC, the base, using the distance formula: \"d+=+sqrt%28%28x%5B1%5D+-+x%5B2%5D%29%5E2+%2B+%28y%5B1%5D+-+y%5B2%5D%29%5E2%29\", and the length of the altitude, or BD.
\n" ); document.write( "Now, take half the product of AC and BD, since the area of a triangle is calculated as \"%281%2F2%29+%2A+base+%2A+height\"
\n" ); document.write( "That's all.......nothing too COMPLEX and/or CONFUSING. \n" ); document.write( "
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