3 years ago a man is four times the age of the daughter. If the product of their ages is 430 what are their present ages? \r
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document.write( "The original problem for this was:
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document.write( "https://www.algebra.com/algebra/homework/word/age/Age_Word_Problems.faq.question.776905.html
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document.write( "https://www.algebra.com/algebra/homework/word/age/Age_Word_Problems.faq.question.776905.html\r
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document.write( "The difference with the above problem (# 1063998) is that it failed to include the words: \"IS NOW.\"
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document.write( "As such, I agree with IKLEYN that it is DEFECTIVE, as age problems with ages that are NON-INTEGERS, are nonsense, in my opinion.
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document.write( "I think IKLEYN misunderstood me. When I referred to the 3 people who responded, I was talking about the 3 who responded to the ORIGINAL problem (# 776905),
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document.write( "not the CURRENT problem (# 1063998). I IMPLORE you to LOOK at the ORIGINAL problem (# 776905) and you'll see what I'm talking about.\r
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document.write( "This is UNBELIEVABLE! 3 other persons responded to the OLDER math problem (# 776905) and all 3 were UNABLE to solve this simple problem. Why so???
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document.write( "And, these people call themselves, TUTORS!\r
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document.write( "This is the ORIGINAL problem, solved a LONG time ago and ONLY yours truly's answer was correct.
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document.write( "3 years ago a father was 4 times as old as his daughter is now. The product of their ages is 430. Calculate their present ages.
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document.write( "Let daughter's, and father's current ages be D, and F, respectively
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document.write( "Then: F - 3 = 4D ----- F = 4D + 3 ----- eq (i)
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document.write( "Also FD = 430 ------ eq (ii)
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document.write( "D(4D + 3) = 430 ----- Substituting
for F in eq (ii)
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document.write( "Solve this to get daughter's age. Then find father's: 
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document.write( "You should get:
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document.write( "Daughter's current age: 
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document.write( "Father's current age:
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