document.write( "Question 1064010: Please show the complete solution to these two related problems;\r
\n" ); document.write( "\n" ); document.write( " Emily rows six miles downstream in 1 hour and her friend Ashley,rowing 1 mile per hour faster,completes the return trip in two hours.\r
\n" ); document.write( "\n" ); document.write( "1) Find the speed of the current (c) and each girl's rowing speed.\r
\n" ); document.write( "\n" ); document.write( "2) If Emily and Ashley were rowing separately,who would complete their first and by how long? Round to the nearest hundredth,if necessary. \n" ); document.write( "
Algebra.Com's Answer #679045 by jorel1380(3719)\"\" \"About 
You can put this solution on YOUR website!
1)Let r be Emily's rowing speed; then Ashley's rowing speed is r+1. And let the speed of the current be c. Then:
\n" ); document.write( "6/r+c=1 and
\n" ); document.write( "6/(r+1)-c=2
\n" ); document.write( "So:
\n" ); document.write( "r+c=6 and
\n" ); document.write( "2r+2-2c=6, or 2r-2c=4
\n" ); document.write( "2r+2c=12
\n" ); document.write( "2r-2c=4
\n" ); document.write( "4r=16
\n" ); document.write( "r=4
\n" ); document.write( "Emily's rowing speed is 4 mph; the current is 2 mph. And Ashley's rowing speed is 5 mph.
\n" ); document.write( "2)Emily's total time:
\n" ); document.write( "6/4+2 + 6/4-2=6/6+6/2=4 hours
\n" ); document.write( "Ashley's total time:
\n" ); document.write( "6/7+6/3=2&6/7 hours
\n" ); document.write( "4-2.8571428571428571428571428571429=1.142857 hours that Ashley would finish ahead of Emily. ☺☺☺☺ \n" ); document.write( "
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