document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1064015>Question 1064015</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a triangle is 44 cm. One of its sides is 4 cm smaller than the other and twice as long as the third side. Find the sides of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #679040 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=679040\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a+b+c = 44<BR>\n" );
document.write( "a = b-4<BR>\n" );
document.write( "c = 2b<BR>\n" );
document.write( "substitute:<BR>\n" );
document.write( "b-4+b+2b = 44<BR>\n" );
document.write( "4b-4 = 44<BR>\n" );
document.write( "4b = 48<BR>\n" );
document.write( "b = 12<BR>\n" );
document.write( "then:<BR>\n" );
document.write( "a = b-4 = 12-4 = 8<BR>\n" );
document.write( "and:<BR>\n" );
document.write( "c = 2b = 2(12) = 24<BR>\n" );
document.write( "-------------------<BR>\n" );
document.write( "check: <BR>\n" );
document.write( "a+b+c = 44<BR>\n" );
document.write( "8+12+24 = 44 Correct<BR>\n" );
document.write( ":<BR>\n" );
document.write( "John </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );