document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1063939>Question 1063939</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a row of 6 counters, 3 are red, 2 are blue and 1 is white. <BR>\n" );
document.write( "Find the number of arrangements in which no red counter is <BR>\n" );
document.write( "next to another red counter.<BR>\n" );
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document.write( "The answer given is 12. Can you draw boxes and explain it to me? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #679005 by </B><A HREF=/tutors/aboutme.mpl?userid=math_helper><B>math_helper(2461)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_helper><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=math_helper><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=679005\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I just solved this one this morning:\r<BR>\n" );
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document.write( "Basically, you have  _B_B_W_   where the _ are spaces for the Red, so 4C3 selections.<BR>\n" );
document.write( "However, the BBW also can be re-arranged in 3 ways because there are 3C1 spaces to place W:  BBW, BWB, and WBB\r<BR>\n" );
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document.write( "Hence, for each of the 4 arrangements of the Red ones, there are 3 arrangements for W so  4x3 = 12.   \r<BR>\n" );
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