document.write( "Question 92582: Solve each absolute value inequality and graph the solution set.
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document.write( "|x-2|> = 3 \n" );
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Algebra.Com's Answer #67898 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! Given to solve and graph: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "You can solve this by setting up two inequalities. The inequalities come from taking the \n" ); document.write( "quantity inside the absolute value signs and preceding it first with a + sign for one inequality \n" ); document.write( "and then preceding it with a minus sign. \n" ); document.write( ". \n" ); document.write( "And since you have an inequality, remember the basic rule that if you multiply or divide both \n" ); document.write( "sides by a negative, then you reverse the direction of the inequality sign. \n" ); document.write( ". \n" ); document.write( "With this in mind, let's begin by writing the inequality using the quantity inside the \n" ); document.write( "absolute value signs preceded by a + sign. \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "and the parentheses can be eliminated without affecting the inequality because the parentheses \n" ); document.write( "are preceded by an implied + sign. This makes the inequality become: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "As you would do in an equation, you can get rid of the -2 on the left side by adding +2 \n" ); document.write( "to both sides to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "This is one solution. It says that x must equal or be greater than 5. \n" ); document.write( ". \n" ); document.write( "Now to the second part of the solution. Take the quantity inside the absolute value signs \n" ); document.write( "and preceded it by a minus sign to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Since the parentheses are preceded by a negative sign, when you remove them you change the \n" ); document.write( "sign of each of the terms inside and the equation becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Next you can get rid of the +2 on the left side by adding -2 to both sides to \n" ); document.write( "get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "We are trying to solve for +x so we need to multiply both sides by -1 to make the x \n" ); document.write( "switch from -x to +x. Don't forget the rule that when you multiply or divide both sides \n" ); document.write( "of an inequality by a negative quantity you reverse the direction of the inequality sign. \n" ); document.write( "So when you multiply both sides by a -1 you get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "This tells you that x must equal or be less than -1. \n" ); document.write( ". \n" ); document.write( "To graph the two solutions to this problem, create a number line, and on that line put \n" ); document.write( "dots at two points ... at -1 and at +5. Then you make the number line heavy or bold \n" ); document.write( "from minus infinity all the way up to (and including) the point at -1. Next you make the \n" ); document.write( "number line heavy all the way from plus infinity down to (and including) the point at +5. \n" ); document.write( ". \n" ); document.write( "The heavy parts of the number line then tell you where values of x will satisfy the original \n" ); document.write( "problem. Note that the number is not heavy between the values of x= -1 and x = +5, so that \n" ); document.write( "is the region in which any value of x will not satisfy the inequality. \n" ); document.write( ". \n" ); document.write( "Let's do a few checkpoints to see whether our answer is correct. \n" ); document.write( ". \n" ); document.write( "How about letting x = 0, a value that is in the region we said should not work. When we \n" ); document.write( "substitute 0 for x in the original problem it becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "This simplifies to \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "and the absolute value of -2 is +2. That means that the inequality becomes \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "and this is not true. So we know that at one value between x=-1 and x= +5 the inequality \n" ); document.write( "will not work. \n" ); document.write( ". \n" ); document.write( "Next let's try letting x= +6. That is in a region that we said x has values that should \n" ); document.write( "work. If you substitute +6 for x in the original problem you get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "and this simplifies to \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "and the absolute value of +4 is +4 so the inequality becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "That works ... so one value in a region that we said should work, does work. \n" ); document.write( ". \n" ); document.write( "Finally, let's let x = -2. That also is in a region that we said should work. Substituting \n" ); document.write( "-2 for x in the original problem makes it become: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "This simplifies to \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "and the absolute value of -4 is +4. So the inequality simplifies to: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "This is true, so we know that when x equals -2, the original inequality holds true. It \n" ); document.write( "helps to verify that our original equation is true. \n" ); document.write( ". \n" ); document.write( "You can try additional values of x to help you confirm to your self that if: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Then the original inequality will be true. \n" ); document.write( ". \n" ); document.write( "Hope this helps you to understand how you can work inequalities of this type. \n" ); document.write( ". \n" ); document.write( " |