document.write( "Question 1063895: Jen does one-quarter of a job in 3 hours. If Nicky works 2 hours more than Jen, she can finish one-sixth of the job. How long does it take to do the job if they work together? \n" ); document.write( "
Algebra.Com's Answer #678975 by ankor@dixie-net.com(22740)\"\" \"About 
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Jen does one-quarter of a job in 3 hours.
\n" ); document.write( "therefore: 4 * 3 = 12 hrs to complete the job
\n" ); document.write( ":
\n" ); document.write( " If Nicky works 2 hours more than Jen, she can finish one-sixth of the job.
\n" ); document.write( "Jen works 3 hrs, therefore N works 5hr, therefore N:
\n" ); document.write( "6 * 5 = 30 hrs to complete the job
\n" ); document.write( ":
\n" ); document.write( "How long does it take to do the job if they work together?
\n" ); document.write( "let t = time required working together
\n" ); document.write( "let completed job = 1
\n" ); document.write( "A shared work equation, each does a fraction of the job.
\n" ); document.write( "The two fractions add up 1
\n" ); document.write( "\"t%2F12\" + \"t%2F30\" = 1
\n" ); document.write( "multiply equation by 60, cancel the denominators
\n" ); document.write( "5t + 2t = 60
\n" ); document.write( "7t = 60
\n" ); document.write( "t = 60/7
\n" ); document.write( "t = 8.57 hrs working together \n" ); document.write( "
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