document.write( "Question 1063823: My book didn't show me how to do this but it asks questions like this anyway.\r
\n" ); document.write( "\n" ); document.write( "The length of any side of a triangle is less than the sum of the lengths of the other two sides. In triangle[PQR], PR= RQ+4 and RQ<11. Write and solve an inequality for PQ.\r
\n" ); document.write( "\n" ); document.write( "Any explanations of steps would be great.
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Algebra.Com's Answer #678927 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
For a given triangle PQR, the sum of any two sides is greater than the third and any side is less than the sum of the other two
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\n" ); document.write( "1) PQ + PR > RQ
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\n" ); document.write( "2) PQ + RQ > PR
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\n" ); document.write( "3) RQ + PR > PQ
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\n" ); document.write( "4) RQ < 11
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\n" ); document.write( "5) PR = RQ + 4
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\n" ); document.write( "by inequality 2) and equation 5)
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\n" ); document.write( "PQ + RQ > RQ + 4
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\n" ); document.write( "6) PQ > 4
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\n" ); document.write( "any side of PQR is less than the sum of the other two sides, also use inequality 4)
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\n" ); document.write( "RQ < PQ + PR < 11
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\n" ); document.write( "use equation 5)
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\n" ); document.write( "RQ < PQ + RQ + 4 < 11
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\n" ); document.write( "7) 0 < PQ < 7
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\n" ); document.write( "combine inequalities 6) and 7)
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\n" ); document.write( "4 < PQ < 7
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