document.write( "Question 93255: I need help with this problem please:\r
\n" ); document.write( "\n" ); document.write( "Lane invested $14,000, part at 15% and part at 2%. If the total interest at the end of the year is $1,060, how much did she invest at 15%?\r
\n" ); document.write( "\n" ); document.write( "Thanks for your help!
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Algebra.Com's Answer #67889 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
.15X+.02(14000-X)=1060
\n" ); document.write( ".15X+280-.02X=1060
\n" ); document.write( ".13X=1060-280
\n" ); document.write( ".13X=780
\n" ); document.write( "X=780/.13
\n" ); document.write( "X=6,000 INVESTED @ 15%
\n" ); document.write( "PROOF
\n" ); document.write( ".15*6000+.02*8000=1060
\n" ); document.write( "900+160=1060
\n" ); document.write( "1060=1060
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