document.write( "Question 93255: I need help with this problem please:\r
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document.write( "Lane invested $14,000, part at 15% and part at 2%. If the total interest at the end of the year is $1,060, how much did she invest at 15%?\r
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document.write( "Thanks for your help! \n" );
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Algebra.Com's Answer #67889 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! .15X+.02(14000-X)=1060 \n" ); document.write( ".15X+280-.02X=1060 \n" ); document.write( ".13X=1060-280 \n" ); document.write( ".13X=780 \n" ); document.write( "X=780/.13 \n" ); document.write( "X=6,000 INVESTED @ 15% \n" ); document.write( "PROOF \n" ); document.write( ".15*6000+.02*8000=1060 \n" ); document.write( "900+160=1060 \n" ); document.write( "1060=1060 \n" ); document.write( " \n" ); document.write( " |