document.write( "Question 1063751: How bad is the heavy traffic? You can jogjog 10 miles in the same time that it takes to travel 20 miles by car. If the car's rate is 9 miles per hour faster than your jogging rate, find the average rate of each. \n" ); document.write( "

Algebra.Com's Answer #678880 by josgarithmetic(39618) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "                  SPEED          TIME          DISTANCE\r\n" );
document.write( "JOG                r              x             10\r\n" );
document.write( "CAR               r+9             x             20\r\n" );
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\n" ); document.write( "\n" ); document.write( " $\"10%2Fr=20%2F%28r%2B9%29\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"1%2Fr=2%2F%28r%2B9%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "Continue and finish. \n" ); document.write( "

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