document.write( "Question 93260: hi there,
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document.write( "I asked the following question before and I had a solution given to me, I do not understand some of it though, some guidance would be great.
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document.write( "s=u.(v-u)/a + 1/2a((v-u)/a)^2
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document.write( "it should end up as v^2=u^2+2as \r
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document.write( "first step was to multiply by 2a giving....
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document.write( "2as=2u(v-u)+(v-u)^2\r
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document.write( "expanding
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document.write( "2as= 2uv-2u^2+v^2-2vu+u^2\r
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document.write( "apparently by collecting terms this is equal to 2as=v^2-u^2, could someone please explain this last step for me \n" );
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Algebra.Com's Answer #67888 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 2as= 2uv-2u^2+v^2-2vu+u^2\r \n" ); document.write( "\n" ); document.write( "apparantly by collecting terms this is equal to 2as=v^2-u^2, could someone please explain this last step for me \n" ); document.write( "--------------- \n" ); document.write( "2uv-2u^2+v^2-2vu+u^2\r \n" ); document.write( "\n" ); document.write( "=2u(v-u) + [v^2-2uv+u^2]\r \n" ); document.write( "\n" ); document.write( "= 2u(v-u) + [v-u]^2\r \n" ); document.write( "\n" ); document.write( "=(v-u)[2u + v-u]\r \n" ); document.write( "\n" ); document.write( "= (v-u)(v+u)\r \n" ); document.write( "\n" ); document.write( "= v^2-u^2\r \n" ); document.write( "\n" ); document.write( "================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |