document.write( "Question 1063623: Given A(-1,4) and B(3,-2). A find the midpoint of AB.
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document.write( "B)Find the equation to the line through A and B. In slope intercept form.
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document.write( "C)General form with integer coefficients \n" );
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Algebra.Com's Answer #678751 by sky1983(10) You can put this solution on YOUR website! the midpoint is the average of the two points \n" ); document.write( "x = (-1+3)/2 = 2/2 = 1 \n" ); document.write( "y = [4+(-2)]/2 = 2/2 = 1 \n" ); document.write( "the midpoint is at (1,1)\r \n" ); document.write( "\n" ); document.write( "to find the equation in slope intercept form, find first the slope \n" ); document.write( "m = [4-(-2)]/[-1-3] = 6/-4 = -3/2 \n" ); document.write( "from y = mx + b, solve for b using any of the given points, in here i will use point A(-1,4) \n" ); document.write( "4 =(-3/2)(-1) + b \n" ); document.write( "4 = 3/2 + b \n" ); document.write( "b=5/2 \n" ); document.write( "so our equation is, \n" ); document.write( "y = (-3/2)x + 5/2\r \n" ); document.write( "\n" ); document.write( "The \"General Form\" of the equation of a straight line is: \n" ); document.write( "Ax + By + C = 0 \n" ); document.write( "y = (-3/2)x + 5/2 \n" ); document.write( "y + (3/2)x - 5/2 = 0 \n" ); document.write( "rearrange \n" ); document.write( "(3/2)x + y - 5/2 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "cheers mate! \n" ); document.write( "sky1983 \n" ); document.write( " |