document.write( "Question 93239: I am so lost, if anyone could please answer this one I'd really appreciate it: What is the domain of g(x) when \"g%28x%29=%28x%2B3%29%2F%282x-5%29\" \n" ); document.write( "
Algebra.Com's Answer #67874 by Earlsdon(6294)\"\" \"About 
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What is the domain of g(x) when:
\n" ); document.write( "\"g%28x%29+=+%28x%2B3%29%2F%282x-5%29\"
\n" ); document.write( "You'll recall, no doubt, that the domain of a function is the set of all possible values of the independent variable, which is x in this case.
\n" ); document.write( "First, we need to examine the denominator of the given function (2x-5) and ask...\"what value of x will cause this to become zero?\"
\n" ); document.write( "You can find out by setting the denominator equal to zero and solving for x.
\n" ); document.write( "\"2x-5+=+0\" Add 5 to both sides.
\n" ); document.write( "\"2x+=+5\" Divide both sides by 2.
\n" ); document.write( "\"x+=+5%2F2\"
\n" ); document.write( "So, when \"x+=+5%2F2\" the denominator of the function becomes zero, and, as you know, mathematics does not allow division by zero. It undefined. Therefore, we must exclude \"x+=+5%2F2\" from the domain. All other real values of x, however, are legal, so we can write the domain as:
\n" ); document.write( "\"%285%2F2%29%3Ex%3E%285%2F2%29\"
\n" ); document.write( "You would read this as...\"all the real numbers not incuding 5/2\"
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