document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1063509>Question 1063509</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Construct a system of two linear equations where (-5,4) is a solution to the first equation but not to the second equation, and where (5,-2) is a solution to your system. Step 1 plot the points given to you and write the equation of that line. Call it L1. Step 2 on the graph draw a second line that will create a system of equations with the desired solution step3 writethe equation of your line call it L2. Follow up questions 1 explain how graph shows your system satisfies the required conditions 2should u have the same equation as your partner for L1 explain why or why not 3 should u have the same equation as your partner for L2 explain why or why not </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #678702 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=678702\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Construct a system of two linear equations where (-5,4) is a solution to the first equation but not to the second equation, and where (5,-2) is a solution to your system. Step 1 plot the points given to you and write the equation of that line. Call it L1. Step 2 on the graph draw a second line that will create a system of equations with the desired solution step3 writethe equation of your line call it L2. <BR>\n" );
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document.write( "Follow up questions 1 explain how graph shows your system satisfies the required conditions 2 should u have the same equation as your partner for L1 explain why or why not 3 should u have the same equation as your partner for L2 explain why or why not.<BR>\n" );
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document.write( "Equation of line thru (-5,4) and (5,-2)<BR>\n" );
document.write( "slope = (4--2)/(-5-5) = 6/-10 = -3/5<BR>\n" );
document.write( "Form:: y = mx + b<BR>\n" );
document.write( "4 = (-3/5)(-5) + b<BR>\n" );
document.write( "4 = 3 + b<BR>\n" );
document.write( "b = 1<BR>\n" );
document.write( "L1:: y = (-3/5)x + 1<BR>\n" );
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document.write( "Equation of L2::<BR>\n" );
document.write( "y = -2<BR>\n" );
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document.write( "Graph::<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28400%2C400%2C-10%2C10%2C-10%2C10%2C%28-3%2F5%29x%2B1%2C-2%29 ALIGN=MIDDLE  ALT=\"graph%28400%2C400%2C-10%2C10%2C-10%2C10%2C%28-3%2F5%29x%2B1%2C-2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "--------------- </SPAN>\n" );
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