document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1063552>Question 1063552</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 9. A company sells a container of mixed nuts that is 12% peanuts and another container that is<BR>\n" );
document.write( "60% peanuts. How many cups of each mixture would be needed to make 12 cups that is 40%<BR>\n" );
document.write( "peanuts?<BR>\n" );
document.write( "4 cups of the 12% peanuts and 8 cups of the 60% peanuts<BR>\n" );
document.write( "8 cups of the 12% peanuts and 4 cups of the 60% peanuts<BR>\n" );
document.write( "5 cups of the 12% peanuts and 7 cups of the 60% peanuts<BR>\n" );
document.write( "3 cups of the 12% peanuts and 9 cups of the 60% peanuts </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #678678 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=678678\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x= cups of 12%<BR>\n" );
document.write( "12-x= cups of 60%<BR>\n" );
document.write( ".12x+.60(12-x)=.40(12)<BR>\n" );
document.write( ".12x+7.2-.60x=4.8<BR>\n" );
document.write( "-.48x=-2.4<BR>\n" );
document.write( "x=5 cups of 12%<BR>\n" );
document.write( "12-x=7 cups of 60%<BR>\n" );
document.write( "expect the number of cups of 60% to be more, because you end up a little closer to 60% than to 12%.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );