document.write( "Question 1063412: a rectangular building whose depth is twice its frontage is divided into two parts by a portion that is 20 ft from and parallel to the front wall.If the rear portion of the building contains 3500 ft^2 find the dimwnsions of the building. \n" ); document.write( "

Algebra.Com's Answer #678658 by KMST(5328) $\"\"$ $\"About$

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$\"x\"$ = frontage of the building, in feet.
\n" ); document.write( "So, the area of the rear portion of the building, in square feet
\n" ); document.write( "is represented by
\n" ); document.write( " $\"20x\"$ ,
\n" ); document.write( "and our equation is
\n" ); document.write( " $\"20x=3500\"$ .
\n" ); document.write( "Solving that equation gives us $\"x=175\"$ .
\n" ); document.write( "so the building's frontage is $\"highlight%28175feet%29\"$ ,
\n" ); document.write( "and so since it's depths is twice its frontage,
\n" ); document.write( "the building's depth is $\"2%2A%28175feet%29=highlight%28350feet%29\"$ . \n" ); document.write( "

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